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Draw a graph of logP and log(1/V) for a fixed amount of gas at constant temperature.

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According to Boyle's law, P=log(1/V)+logK
Comparing it to y=mx+c, we find that the graph of logPvslog(1/V) should be a straight line with slope equal to k, i.e.
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Updated on:21/07/2023
Class 11 CHEMISTRY STATES OF MATTER

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